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December 22, 2014

December 22, 2014

Posted by **Goldfish** on Wednesday, February 10, 2010 at 5:34am.

(x^3) / (x^3 - 2x^2 + 3x - 18)

I tried using long division, but I could only get a quotient of 1, and a remainder of 2x^2 - 3x + 18

Did i do something wrong?

- Quadratic Long Division (sos Reiny!) -
**drwls**, Wednesday, February 10, 2010 at 6:01amOne does not use polynomial long division to apply the method of partial fractions. Try factoring x^3 - 2x^2 + 3x - 18 instead. The factors are (x-3)and (x^2 +x -6).

The next step is, I believe to express your ratio in terms of

C/(x-3) + (Ax + B)/(x^2 +x -6).

where A, B and C are constants. There should be three values that work.

- Quadratic Long Division (error) -
**drwls**, Wednesday, February 10, 2010 at 6:05amChange (x^2 +x -6) to (x^2 +x +6)

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