posted by Joseph on .
Ethanol has a heat of vaporization of 38.56 KJ/Mol. And a normal boiling point of 78.4 degrees celcius.
WHAT is the vapor pressure of ethanol at 18 degrees celcius??
Note the correct spelling of celsius.
Use the Clausius-Clapeyron equation. One of the points is the normal boiling point (where the vapor pressure is 760 torr) and the other point is vapor pressure at 18 C. Don't forget to use Kelvin for temperature.
Thanks. But I'm still getting it wrong, cause maybe the sig figs are off by a little. What did you get for this problem?
Show your work (best in a new post together with the problem) so it will get to the top of the list again) and I will help you find the error.