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Physical Chemistry

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Determine the temperature change when 18.0 g of the following salt is dissolved in 190. g of water. The specific heat capacity of water is 4.184 J·K-1g-1. The enthalpies of solution in the table are applicable. Do not take the added mass of the salt into account when calculating q for the solution.

dH for KCl: +17.2 kJ/mol
dH for MgBr2: -185.6

Have tried using q= mCdT, but keep getting something wrong... Thanks in advance

  • Physical Chemistry -

    A negative enthalpy of solution means that the process of dissolving is exothermic. For MgBr2, the molar mass is 184.1 g/mol so 18 g is 0.098 moles. That would release q = 18.1*10^3 J of heat.

    Now use your q = mC dT formula.

    dT = q/(mC) = 18.1*10^3 J/(190g*4.184 J·K-1g-1)= 23 C

    Is that what you got?


  • Physical Chemistry -

    no I didn't get that, but I was adding both 18g of the salt and 190 g of water for the m used in the equation. I'm still a little confused with the signs...I thought if it is releasing heat then q would be negative? I did manage to get the same value for q I just had it negative instead....

  • Physical Chemistry -

    If it releasing heat, q is positive but the enthalpy of solution (dH) is negative

  • Physical Chemistry -

    Ok, thanks for your help

  • Physical Chemistry -

    Just want to double for KCl, because it is endothermic, my q should then be negative?

  • Physical Chemistry -


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