Posted by **Reed** on Wednesday, February 10, 2010 at 1:20am.

Point A is 5 m from a loudspeaker. At point B, the loudspeaker sounds half as loud as at point A. How far is point B from the loudspeaker?

I get 50 m, but the answer is supposed to be 15.8 m. I need to know what I'm doing wrong.

By my (apparently flawed) reasoning:

Point A is 10 dB louder than Point B because +10 db = ~2x louder

+10 dB = *10 Intensity (I), because the dB scale is log 10

Therefore, I(A) = 10*I(B) and I(A)/I(B) = 10

Using the formula I(A)/I(B) = r(B)/r(A), I find that

10 = r(B)/r(A)

Plug in 5 m for the value of r(A), and solve for r(B), which comes out to be 50 m.

So what am I screwing up?

Thanks for your help.

- Physics -
**drwls**, Wednesday, February 10, 2010 at 1:45am
It is not clear to me what they mean by "sounding" half as loud. The sound power per area (intensity) will be down by a factor of 2 if you move sqrt2 times farther away, to a distance of 7.07 meters in this case. The sound level there is 3 dB down from Point A.

At 15.8 m the distance is 3.16 times farther and the sound power is 3.16^2 = 10 times less, which is 10 dB down. Apparently they are saying that 10 dB down "sounds like" half as loud. Other websites I have looked at also make the statement that 10 dB down sounds half as loud, so I guess it is an accepted rule of thumb. i had never heard it before.

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