Elemental Sulfur can be formed through the combustion of Hydrogen Sulfide (found in Methane gas) give in equation H2 S +O--->S + H2 4
tell how much sulfur is made from 250 grams of methane
I think I responded to this question earlier and I THINK by the same poster but if not I apologize. At any rate, I can't answer the question
1. I don't know what H2 S is.
2. There is no such thing as O by itself.
3. What is H2 4?
4. Even if I knew the answers to 1-3, we still need to know the percent S in methane or some way to calculate it.
The real equation should be something like this:
H2S + O2 -> S + H2O
Balancing the equation:
2 H2S + O2 -> 2S + 2H2O
The question does not mention anything about methane, CH4.
Also, The sulfur in the equation (mistaken as methane, i suppose) is one of the product, not the reactant.
To determine how much sulfur can be formed from 250 grams of methane, we need to understand the stoichiometry of the chemical equation provided.
The balanced equation is: H2S + O2 → S + H2O
From the equation, we can see that 1 mole of H2S produces 1 mole of S. This means that the mole ratio between H2S and S is 1:1.
Now, let's calculate the molar mass of methane (CH4) and H2S.
The molar mass of carbon (C) is 12.01 g/mol, and hydrogen (H) is 1.01 g/mol. So the molar mass of methane (CH4) is:
1(12.01 g/mol) + 4(1.01 g/mol) = 16.05 g/mol.
The molar mass of sulfur (S) is 32.07 g/mol, and hydrogen (H) is 1.01 g/mol. So the molar mass of H2S is:
2(1.01 g/mol) + 32.07 g/mol = 34.09 g/mol.
Now, we can set up a proportion to find the number of moles of methane (CH4) present in 250 grams.
(250 g) / (16.05 g/mol) = x mol
Solving for x gives:
x ≈ 15.57 mol
Since the mole ratio between H2S and S is 1:1, the number of moles of sulfur formed will be the same as the number of moles of H2S.
Therefore, the number of moles of sulfur formed from 250 grams of methane is approximately 15.57 mol.
Finally, we can calculate the mass of sulfur formed using the molar mass of sulfur (32.07 g/mol):
Mass of sulfur formed = (15.57 mol) x (32.07 g/mol) ≈ 499.85 grams
Therefore, approximately 499.85 grams of sulfur can be formed from 250 grams of methane.