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October 25, 2014

Posted by **M.A.** on Tuesday, February 9, 2010 at 9:45am.

4

6

9

24

Explain

- math -
**drwls**, Tuesday, February 9, 2010 at 11:31amThe correct answer is nine.

Student A can get any of three books: b, c or d. Assume he gets b. Then there are only three possibilities of distributing the remaining three (a, c and d) among students B, C and D. B can get a, c or d, but there is only one way to distribute the other two. The same logic applies to each of the three possible assignments to student A.

3 x 3 = 9

- math -
**Dawn**, Tuesday, February 9, 2010 at 11:34amhey how come u didn't mind giving the correct answer this time drwls????

- math (for Dawn) -
**drwls**, Tuesday, February 9, 2010 at 1:05pmThe hardest part of the problem for me was figuring out a method of solution. My first attempt, using factorial numbers, was wrong. So I took more time to think about it, and even made a list of possible rearragements. Computing the number was easy, once the logic was done properly.

Students who are only looking for a number to plug into a computerized test sheet are missing the fun of mathematics, and will probably never master the subject.

- math -
**bobpursley**, Tuesday, February 9, 2010 at 1:06pmLet the students be abcd

and the exams ABCD

Here are the possible ways to distribute exams:

BCDA

BDAC

BADC

CADC

CDAB

CDBA

DABC

DCAB

DCBA

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