A ball is thrown upward from a platform 4.6 m high with a speed of 23 m/s at an angle of 40 o from the horizontal. What is the magnitude of its velocity when it hits the ground?
Regardless of the angle that it is thrown, the kinetic energy at impact will increase by M g H, where H = 4.6 m.
Although you do not know M, it will cancel out when you write
(M/2)Vo^2 + M g H = (M/2)Vinal^2
Vfinal^2 = Vo^2 + 2 g H