Is the answer 51g H2O for my question what mass of water is needed to react with 32.9g LI3N?
There is no connection between this post of yours and any others you previously made.
I found 51.1.
Yes
To determine the mass of water needed to react with 32.9g of LI3N, we need to know the balanced chemical equation for the reaction between LI3N and water. Without that information, it is not possible to provide a precise answer.
However, in general, we can use stoichiometry to determine the masses of substances involved in a chemical reaction. Here's a general method to calculate the mass of water required for a reaction:
1. Write the balanced chemical equation for the reaction between LI3N and water, if it is given. For example:
2 LI3N + 3 H2O → 6 NH3 + 3 LiOH
2. Based on the stoichiometry of the balanced equation, determine the molar ratio between LI3N and water. In the given balanced equation, the ratio is 2:3, which means that 2 moles of LI3N react with 3 moles of water.
3. Convert the given mass of LI3N (32.9g) to moles by dividing it by the molar mass of LI3N. The molar mass of LI3N (lithium nitride) can be calculated using the atomic masses of lithium (Li) and nitrogen (N) found on the periodic table.
4. Use the molar ratio from step 2 to determine the moles of water required. Multiply the moles of LI3N from step 3 by the ratio of moles of water to moles of LI3N.
5. Convert the moles of water obtained in step 4 to grams by multiplying by the molar mass of water (H2O).
By carrying out these calculations, you will get the accurate mass of water needed to react with the given amount of LI3N.