calculus
posted by sam on .
can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx
I just don't understand how to do it....

Isn't there are identity
sin2x=12sin^2 x ? 
I don't understand what you are saying. there is no sin2x in my equation i don't think
i have to evaluate the integral 2(sin^2x) 
Try
sin(x)sin(y)=(1/2)(cos(xy)cos(x+y))
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.