Posted by **sam** on Sunday, February 7, 2010 at 6:45pm.

can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx

I just dont understand how to do it....

- calculus -
**bobpursley**, Sunday, February 7, 2010 at 6:56pm
Isn't there are identity

sin2x=1-2sin^2 x ?

- calculus -
**sam**, Sunday, February 7, 2010 at 7:03pm
I dont understand what you are saying. there is no sin2x in my equation i dont think

i have to evaluate the integral 2(sin^2x)

- calculus -
**MathMate**, Sunday, February 7, 2010 at 7:36pm
Try

sin(x)sin(y)=(1/2)(cos(x-y)-cos(x+y))

Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.

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