posted by sam on .
can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx
I just don't understand how to do it....
Isn't there are identity
sin2x=1-2sin^2 x ?
I don't understand what you are saying. there is no sin2x in my equation i don't think
i have to evaluate the integral 2(sin^2x)
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.