Posted by sam on Sunday, February 7, 2010 at 6:45pm.
can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx
I just don't understand how to do it....

calculus  bobpursley, Sunday, February 7, 2010 at 6:56pm
Isn't there are identity
sin2x=12sin^2 x ?

calculus  sam, Sunday, February 7, 2010 at 7:03pm
I don't understand what you are saying. there is no sin2x in my equation i don't think
i have to evaluate the integral 2(sin^2x)

calculus  MathMate, Sunday, February 7, 2010 at 7:36pm
Try
sin(x)sin(y)=(1/2)(cos(xy)cos(x+y))
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.
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