Lithium nitride reacts with water to form ammonia and aqueous lithium hydroxide.

Li3N(s) + 3H2O(l) > NH3(g) + 3LiOH(aq)

What mass of water is needed to react with 32.9 g Li3N?

1) Balance the equation.

It is already balanced.

2) From the balanced equation, determine the mole ratios for the elements/compounds of interest.
1 mole Li3N = 3 moles H2O

3) Determine how many moles of one of the compounds you have.
You have 32.9 grams of Li3N. How many moles is that? To find out, multiply 32.9 grams by the reciprocal of the molar mass for the compound.
32.9 g Li3N (1 mole Li3N / x grams)

4) Multiply the moles you have for the first compound, by the mole ratio: this will tell you how many moles of the second compound you need.

Is the answer 51 g H2O?

To determine the mass of water needed to react with 32.9 g of Li3N, we need to use the stoichiometry of the balanced chemical equation. Let's calculate it step-by-step:

Step 1: Calculate the molar mass of Li3N.
The molar mass of Li3N can be calculated by adding the atomic masses of lithium (Li) and nitrogen (N):
Li: 6.941 g/mol
N: 14.007 g/mol
Therefore,
Molar mass of Li3N = (3 * Li) + N = (3 * 6.941) + 14.007 = 34.243 g/mol

Step 2: Convert the given mass of Li3N to moles.
To convert grams to moles, divide the given mass by the molar mass of Li3N:
32.9 g / 34.243 g/mol = 0.960 mol

Step 3: Use the mole ratio from the balanced chemical equation.
According to the balanced equation, 1 mole of Li3N reacts with 3 moles of water (H2O). Therefore, we need to multiply the number of moles of Li3N by the mole ratio:
0.960 mol Li3N * (3 mol H2O / 1 mol Li3N) = 2.88 mol H2O

Step 4: Convert moles of water to grams.
To convert moles to grams, multiply the number of moles by the molar mass of water (H2O):
2.88 mol H2O * 18.015 g/mol = 51.902 g

Therefore, approximately 51.902 grams of water are needed to react with 32.9 grams of Li3N.

To find the mass of water needed to react with 32.9 g of Li3N, we need to use the information from the balanced chemical equation.

The balanced equation tells us that 1 mole of Li3N reacts with 3 moles of water. So we first need to find the number of moles of Li3N in 32.9 g.

Step 1: Calculate the molar mass of Li3N.
The molar mass of Li3N is calculated by adding up the atomic masses of each element in the compound.
Li: 6.94 g/mol
N: 14.01 g/mol
Molar mass of Li3N = (3 × 6.94) + 14.01 = 34.81 g/mol

Step 2: Convert the mass of Li3N to moles.
To convert grams to moles, divide the mass by the molar mass.
Number of moles of Li3N = 32.9 g / 34.81 g/mol ≈ 0.944 mol

Step 3: Determine the moles of water needed.
Since the molar ratio between Li3N and H2O is 1:3, for every mole of Li3N, we need 3 moles of water.
Moles of water needed = 3 moles of Li3N × 3 moles of H2O per mole of Li3N = 9 moles of H2O

Step 4: Convert moles of water to grams.
To convert moles to grams, multiply the number of moles by the molar mass of water.
Molar mass of H2O = (2 × 1.01) + 16.00 = 18.02 g/mol
The mass of water needed = 9 moles of H2O × 18.02 g/mol ≈ 162.18 g

Therefore, approximately 162.18 grams of water are needed to react with 32.9 grams of Li3N.