Wednesday

April 23, 2014

April 23, 2014

Posted by **Katherine** on Sunday, February 7, 2010 at 5:22pm.

- Physics -
**bobpursley**, Sunday, February 7, 2010 at 5:34pmWell, E = kq/r^2

E(5)=10

E(10)=15

E(5)=10=kQ/(p+.05)^2

E(10)=15=kQ/(p+.1)^2

divide the first equation by the second:

2/3 = [(P+.1)/(P=.05)]^2

take the sqrt of both sides, solve for P

Then put P into either equation, solve for Q

- Physics -
**drwls**, Sunday, February 7, 2010 at 5:47pmSince the E-field is pointed along the +x axis at locationa along the x axis, the point charge that causes the field but also be on the x axis. The distance from the point charge to (5,0) must be sqrt (2/3) = 0.8165 times the distance from the point to (10,0), because the field is 2/3 as strong at (5,0) as it is at (10,0).

The only way you can make this happen is to have the point charge be positive and located to the left x = 0.

**Related Questions**

Physics - The electric field at the point x=5.00 cm and y=0 points in the ...

physics - The electric field at the point x = 5.00cm and y = 0 points in the ...

physics - The electric field at the point and points in the positive direction ...

physics - Two point charges, 4.0×10-6 C and -1.0×10-6 C, are located on the x ...

physics - 10. The following three point charges are placed on the x axis: +5.0 ...

PHYSICS - Three small spheres are placed at fixed points along the x-axis, whose...

PHYSICS - Three small spheres are placed at fixed points along the x-axis, whose...

physics - please check: Two point charges, initially 1 cm apart, are moved to a ...

science - A 1.98 10-9 C charge has coordinates x = 0, y = −2.00; a 2.73 10...

PHYSICS - 1. Why is an electric field considered to be a vector quantity? 2. ...