Thursday

April 24, 2014

April 24, 2014

Posted by **sam** on Sunday, February 7, 2010 at 4:23pm.

- math -
**Damon**, Sunday, February 7, 2010 at 5:54pmlet u = (2t+1)

du = 2 dt so dt = .5 du

so

.5 integral du sin u/cos^2u

try 1/cos u

d/du (1/cos u) = -sin u/cos^2 u

You can take it from there :)

**Related Questions**

Trig - sin^4t-cos^4t/sin^2t cos^2t= sec^2t-csc^2t i have =(sin^2t+cos^2t)(sin^2t...

CALC - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I used u ...

Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...

Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...

calc: arc length - find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x...

ALGEBRA/PLEASE HELP - have the answer and would love confirmation. VERY ...

ALGEBRA - I have the answer and would love confirmation. VERY APPRECIATED! Find ...

Calculus - I need help with this integral. w= the integral from 0 to 5 24e^-6t ...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...