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posted by sam on Sunday, February 7, 2010 at 4:23pm.
how would i find the integral of sin (2t+1)/cos^2(2t+1) dt
let u = (2t+1) du = 2 dt so dt = .5 du so .5 integral du sin u/cos^2u try 1/cos u d/du (1/cos u) = -sin u/cos^2 u You can take it from there :)
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