Posted by sam on Sunday, February 7, 2010 at 4:23pm.
how would i find the integral of sin (2t+1)/cos^2(2t+1) dt

math  Damon, Sunday, February 7, 2010 at 5:54pm
let u = (2t+1)
du = 2 dt so dt = .5 du
so
.5 integral du sin u/cos^2u
try 1/cos u
d/du (1/cos u) = sin u/cos^2 u
You can take it from there :)