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November 1, 2014

November 1, 2014

Posted by **Momo** on Saturday, February 6, 2010 at 6:46pm.

3x-y-7<0

x+5y+3>=0

This is my thought process in this:

The first equation I can solve for y since we don't have to worry what x is. And I get y>3x-7.

The second one, however, y is being multiplied by 5, so I can't just divide by 5 on both sides because I don't know if the value of y will be positive or negative (and then I'll have to switch the sign).

...So I don't know about the second equation. Help please?

Thank you!

- Math -
**Damon**, Saturday, February 6, 2010 at 6:52pmx+5y+3>=0

5 y > -x -3

y > -x/5 -3/5

You divided by a positive number, so there is no reason to reverse the direction of the arrow. Now graph that line and shade above it.

- Math -
**Reiny**, Saturday, February 6, 2010 at 6:55pm5y ≥ -x - 3

but you are dividing by 5, so you don't have to worry about the inequality sign.

so

y ≥ -x/5 - 3/5

Now in each case, the equation becomes the boundary.

So for the first one, draw a dotted line, and shade in everything above that line.

For the second, draw a dotted line and shade in everything above that line.

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