Posted by Sandhya on Saturday, February 6, 2010 at 6:45pm.
Figure the Electric field from the charged disk along the axis at a distance z, given R
http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/elelin.html#c3
Now, given that expression, then you know from the geometry with the angle theta the string makes from disk,
tanTheta=Eq/mg
But CosineTheta=R/L
and sinTheta=sqrt((L^2-R^2)/L^2) or
sinTheta=sqrt(1-(R/L)^2)
but sinTheta/cosTheta= tan Theta, so
Eq/mg=sqrt(1-(R/L)^2) *L/R
Eq/mg=sqrt((L/R)^2-1)
and now you can solve for L
Remember in your E expression, z=Sqrt(L^2-R^2)
As you can tell, some algebra will be required. Get a nice pad of paper.
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