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October 24, 2014

October 24, 2014

Posted by **Chan** on Saturday, February 6, 2010 at 4:34pm.

Oppositely charged parallel plates are separated by 5.34 mm. A potential difference of 600 V exists between the plates.

(a) What is the magnitude of the electric field between the plates?

___ N/C

(b) What is the magnitude of the force on an electron between the plates?

____ N

(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.89 mm from the positive plate?

___ J

- physics -
**Priscilla**, Saturday, February 6, 2010 at 5:08pmDid they mention the exact numbers of the charges of the parallel plates?

- physics -
**Damon**, Saturday, February 6, 2010 at 5:26pmField strength E times distance between plates = Voltage difference

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