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Posted by on Saturday, February 6, 2010 at 4:34pm.

Hi! could anyone help me please, I have no idea how to this at all. I try to it but, the did not get the right answer. Thank for your help
Oppositely charged parallel plates are separated by 5.34 mm. A potential difference of 600 V exists between the plates.
(a) What is the magnitude of the electric field between the plates?
___ N/C

(b) What is the magnitude of the force on an electron between the plates?
____ N

(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.89 mm from the positive plate?
___ J

  • physics - , Saturday, February 6, 2010 at 5:08pm

    Did they mention the exact numbers of the charges of the parallel plates?

  • physics - , Saturday, February 6, 2010 at 5:26pm

    Field strength E times distance between plates = Voltage difference

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