Posted by Sandra on Saturday, February 6, 2010 at 2:27pm.
They tell you what the charges are. There are three +2nC charges and one -2nC charge.
They ask you for the FIELD at the center of the square, not the force. There is no point charge there.
Thank you for clearing that up!
I'm getting a wrong answer once again for this question though.:( I tried it your way, but I have a feeling I'm making a mistake somewhere. Please help!
Here's what I did:
For the -ve charge located at the top right coner of the square: there are 3 forces acting on it. 1 pointing left, 1 pointing down and one pointing diagonally towards the center of the square.
I found each of these 3 forces; where the one pointing left (F1) and up(F3) are of equal magnitude and F2 is the one one that is pointing .
F1 = F3 = k(2*10^-9)(2*10^-9) / (0.04)^2 = 2.248E-5
F2 = k(2*10^-9)(2*10^-9) / (0.05657)^2 = 1.1239E-5
(Note: 0.05657 = sqrt(0.04^2 + 0.04^2) = the distance between the diagonally located +ve and -ve charges)
Since F2 was a diagonal force, I found its components F2x and F2y:
F2x = F2cos45 = 7.947E-6
F2y = F2sin45 = 7.947E-6
Now the net force on the -ve charge was found :
Fnet = sqrt( (F1+F2x)^2 + (F3+F2y)^2 ) = 4.303E-5
E = F/q = 4.303E-5 / 2E-9 = 21514.48
You said this electric field should be doubled,
so my final answer for this question was:
Etot = 43028.96 N/C or 43.0 kN/C
This answer was wrong though when I submitted it. If it's possible, can you please direct me to the mistake I'm making?
Only two charges contribute to the field at the center as WLS said. The two positive charges that are not opposite the negative charge cancel each other at the center of the square. Read WLS instructions again.
Also you are not interested on forces on the negative charge. You are interested in the field at the center of the square.
ok..so how would we find the forces acting at the center of the field? There will be two forces acting, one form the negative and one from the positive charge right? But if we use Coulomb's Law here.. wouldn't we need a charge in the center? I don't understand how Coulomb's law i.e Fe = kq1q2/r^2 can be applied here...