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November 24, 2014

November 24, 2014

Posted by **ucieng** on Saturday, February 6, 2010 at 1:32pm.

(a) the work done by this force on the particle

(b) the change in the potential energy of the system

(c) the kinetic energy the particle has at x = 5.80 m if its speed is 3.00 m/s at x = 1.40 m

- Physics -
**drwls**, Saturday, February 6, 2010 at 2:10pm(a) The work done is the integral of F dx from 1.4 to 5.8.

If you do not know how to integrate, multiply the AVERAGE force by 4.4 m. The average force is in this case the value at x = 3.60 m

(b) The P.E. change is MINUS the work done in part (a). Just change the sign.

(c) To get the new value of kinetic energy, add the work done to (1/2) M V^2, where Vo = 3 m/s

(K.E.)final = (Work done)+ (M/2)Vo^2

- Physics -
**ucieng**, Saturday, February 6, 2010 at 2:33pmThanks so much for your help drwls!

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