Posted by ucieng on Saturday, February 6, 2010 at 1:32pm.
(a) The work done is the integral of F dx from 1.4 to 5.8.
If you do not know how to integrate, multiply the AVERAGE force by 4.4 m. The average force is in this case the value at x = 3.60 m
(b) The P.E. change is MINUS the work done in part (a). Just change the sign.
(c) To get the new value of kinetic energy, add the work done to (1/2) M V^2, where Vo = 3 m/s
(K.E.)final = (Work done)+ (M/2)Vo^2
Thanks so much for your help drwls!
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