Posted by **Sandra** on Saturday, February 6, 2010 at 1:24pm.

Hi, O tried this question, but I'm getting an answer of 0.99 which rounds to 1, but it was not given as one of the answer choices...can u tell me where I'm going wrong?

What I did was used the following simplified formula:

Volume*density*g =q*E ; where I solved for q.

Then I divided q/e(elementary charge) to find the ratio..

In Robert Millikan's experiment a constant electric field along the vertical axis is obtained with two charged plates, one located above and on below the experimental set-up. The electric field is directed downwards. An oil drop of radius 1.48 μm and density 0.81 g/cm3 is levitated in the chamber when an electric field of 1.7 x 105N/C is applied. Find the charge on the drop as a multiple of the elementary charge e.

the choices were:

2

3

4

5

6

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