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September 1, 2014

September 1, 2014

Posted by **Salman** on Friday, February 5, 2010 at 6:25pm.

- Maths -
**bobpursley**, Friday, February 5, 2010 at 6:32pmWEll, r has to be 9(center with radius 9)

x^2+y^2=9

x^2+(y-17/2)^2= (289/4)

subtract the first equation from the second

(Y-17/2)^2-y^2=289/4 - 9

-17y+289/4=289/4-9

y= 9/17 at the point of intersection.

sinTheta= 9/17*3= 9/51

check my work.

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