Posted by **anonymous** on Friday, February 5, 2010 at 5:35pm.

How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?

- mathematics -
**drwls**, Friday, February 5, 2010 at 5:38pm
8 (teams) x 7 (possible opponents of each team) / 2 = 28

The division by two is necessary to avoid counting each game twice.

- mathematics -
**drwls**, Friday, February 5, 2010 at 5:41pm
I should have multiplied by 2 since each pair of teams plays twice. That makes the final number 56

## Answer this Question

## Related Questions

- math - How many games are played in a women's soccer conference if there are ...
- math: Am I right? - How many games are played in a women’s soccer conference if ...
- Math - How many games are played in a soccer competition if there are 7 teams ...
- math - How many games are played in a soccer competition if there are 7 teams ...
- Math - If each 11 football teams In a college athletic conference played each of...
- MATH - There are 32 teams in the NFL. Sixteen of the teams are in the American ...
- MATH! URGENT!!! - There are 32 teams in the NFL. Sixteen of the teams are in the...
- 8th grade math - There are 32 teams in the NFL. Sixteen of the teams are in the ...
- Math - The function of g += t^2-t represents the total number of games played by...
- algebra 2 homework check - Ruth is scheduling a soccer tournament in which 64 ...

More Related Questions