Posted by **anonymous** on Friday, February 5, 2010 at 5:35pm.

How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?

- mathematics -
**drwls**, Friday, February 5, 2010 at 5:38pm
8 (teams) x 7 (possible opponents of each team) / 2 = 28

The division by two is necessary to avoid counting each game twice.

- mathematics -
**drwls**, Friday, February 5, 2010 at 5:41pm
I should have multiplied by 2 since each pair of teams plays twice. That makes the final number 56

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