Posted by anonymous on Friday, February 5, 2010 at 5:35pm.
How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?

mathematics  drwls, Friday, February 5, 2010 at 5:38pm
8 (teams) x 7 (possible opponents of each team) / 2 = 28
The division by two is necessary to avoid counting each game twice.

mathematics  drwls, Friday, February 5, 2010 at 5:41pm
I should have multiplied by 2 since each pair of teams plays twice. That makes the final number 56
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