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August 31, 2014

August 31, 2014

Posted by **ben** on Thursday, February 4, 2010 at 10:52pm.

- algebra -
**Anonymous**, Thursday, February 4, 2010 at 11:33pmYour total pay for the 2 jobs must be at least 245 dollars.

Pay1 + Pay2 >= 245

The pay for your first job, cleaning, is 8 dollars times the number of hours, h, worked at that job.

Pay1 = 8h

So:

8h + Pay2 >= 245

The pay for your second job, sales, is 6 dollars times the number of hours worked at that job.

Pay2 = 6 * SalesHours

or

Pay2 = 6x

So:

8h + 6x >= 245

That's one inequality.

We also know that the total number of hours worked, h + x, cannot exceed 34. So:

h + x <= 34

There's a second inequality. Almost done.

It is impossible to work less than 0 hours at a job, so both h and x, individually, can be a minimum of 0. Therefore:

h >= 0 <= x

So the final set of inequalities is as follows:

8h + 6x >= 245

h + x <= 34

h >= 0 <= x

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