posted by Kelsie .
How do I put an equation into standard form, Ax+Bx=C?
I have the given points (-1,3) and (2,-4).
Also, how do you write an equation in standard form when perpendicular through another?
[the question is "through (-1,2) and perpendicular to 2x-3y=-5]
first use y2-y1/x2-x1 to find the slope
then(assuming the equation is parellel)use point slope form y-y=slope(x-x)
then to put it in standard form it must be in the Ax+By=C form with no fractions and the leading coefficient cannot be negative.
the way i would work it is first move the equation to standard form because i find it easier to work it that way.
an equation perpendicular to this equation would have a slope of -3/2 because perpendicular lines have opposite recirocal slopes. now use point slope.
now move the equation back to standard form.