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September 18, 2014

September 18, 2014

Posted by **harpreet** on Thursday, February 4, 2010 at 4:40pm.

- trig -
**Reiny**, Thursday, February 4, 2010 at 4:45pmset t = 10 (time from 1998 to 2008)

P(10) = 80(.98)^10

= 65

- trig -
**rickhansen**, Thursday, February 4, 2010 at 4:46pmwell this is how i think u do it

since t at the starting is 1998, take that as basically = 0. from there subtract 1998 from 2008 to get ur value for t. one u have that solve for p

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