Posted by Kate on Thursday, February 4, 2010 at 4:22pm.
How do I solve this problem:
A particular wire has a current of 10A.
A) How many electrons pass a fixed point every 5 seconds?
B)If a wire has a radius of 2 x 10^(3) m and the electron drift speed is 2.63 x 10^(5) m/s, determine the number density of electrons in the wire.
The teacher posts the answers for us, so the answer for
A) 3.125 x 10^(20) e^()
B) 1.89 x 10^(29) e^()/ m^3

College Physics  drwls, Thursday, February 4, 2010 at 7:42pm
It looks like you are switching names. Why?
A) Current (in Amperes) is charge passing by per second.
B) Current = (free electron number density)x (drift speed) x (cross sectional area)
Solve for the FREE electron density. (Electrons that remain attached to the nuclei of the conductor atoms are not included).

College Physics  Kate, Sunday, February 7, 2010 at 12:08am
Thanks for the help! And BTW, I am not switching my name.
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