Posted by ann on Thursday, February 4, 2010 at 2:38pm.
The capacitor with the dielectric will have 4.5 times the C of an empty capacitor with same area and gap size.
Since E = (1/2)CV^2, the dielectric-filled capacitor will require only 1/4.5 = 22.2% of the value of V^2 of the empty one, to have the same stored energy.
(Vfilled)^2 = 12^2/4.5 = 32 Volt^2
Vfilled = 5.66 Volts
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