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December 18, 2014

December 18, 2014

Posted by **Momo** on Wednesday, February 3, 2010 at 10:48pm.

12x^3-23x^2-3x+2=0 is 2. Find all other solutions.

I tried rearranging the equation to factor by grouping, but that 23x^2 is bothersome and I can't get the right answers (I know the answers are 2, 1/4, and -1/3).

Help?

Thank you!

- Math -
**Reiny**, Wednesday, February 3, 2010 at 10:57pmsince you were told that x=2 is a solution, you know that x-2 must be a factor and must divide evenly into your expression.

So use either long division or synthetic division to change your equation to

(x-2)(12x^2 ...........) = 0

since your second factor is a quadratic you can use the quadratic formula to solve that.

(But since you know the solutions, we can conclude that the other factors have to be (4x-1)(3x+1) )

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