can someone help me on this question
ive been stuck on it for almost an hour
The mean of two numbers is 5. The sum of four times one number and three times the other number is 2. Find the numbers.
can u help me get start it by giving me the formula
please and thank you
10= N+M
4N+3M=2
from the first, N= 10-M
then
4(10-M)+3M=2
solve for M first.
why 10=N+M???
thank you
Of course, I can help you with that! To solve this problem, we will set up a system of equations based on the given information.
Let's assume that the two numbers are represented by variables x and y.
Based on the given information, we have two equations:
1. The mean of two numbers is 5:
(x + y) / 2 = 5
2. The sum of four times one number and three times the other number is 2:
4x + 3y = 2
To solve this system of equations, we can use the method of substitution or elimination.
Let's start with the first equation and solve it for one variable in terms of the other:
(x + y) / 2 = 5
x + y = 10
x = 10 - y
Now, substitute this expression for x in the second equation:
4x + 3y = 2
4(10 - y) + 3y = 2
40 - 4y + 3y = 2
40 - y = 2
-y = 2 - 40
-y = -38
y = -38 / -1
y = 38
Now that we have the value of y, we can substitute it back into the first equation to find the value of x:
x + 38 = 10
x = 10 - 38
x = -28
Therefore, the two numbers are -28 and 38.
I hope this helps! Let me know if you have any other questions.