Posted by Pema on Wednesday, February 3, 2010 at 7:27pm.
In triangle ABC, sinA=0.6, a=10 and b=7. Find sinB

trig  Damon, Wednesday, February 3, 2010 at 8:08pm
sin A/a = sin B/b law of sines
so
sinB = (b/a) sinA
= .7 sin A = .7*.6 = .42