The centers of a 8 kg lead ball and a 100 g lead ball are separated by 13 cm. What gravitational force does each exert on the other?
Use the Newton Universal Law of gravity.
F = G*M1*M2/R^2
Look up the value of G if you don't know it.
Make sure M1 and M2 are both in kg. The lead ball mass is 0.100 kg
Your answer is confusing
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To calculate the gravitational force between two objects, we can use Newton's law of universal gravitation, which states that the gravitational force F between two objects is given by the equation:
F = (G * m1 * m2) / r^2
Where:
F is the gravitational force
G is the gravitational constant (approximately 6.674 × 10^-11 N⋅m^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects
In this case, we have an 8 kg lead ball and a 100 g lead ball, with a separation distance of 13 cm (which we need to convert to meters).
Let's calculate the gravitational force exerted by each ball on the other:
For the 8 kg lead ball:
m1 = 8 kg
m2 = 0.1 kg (100 g converted to kg)
r = 0.13 m (13 cm converted to meters)
Using the equation, we have:
F1 = (G * m1 * m2) / r^2
F1 = (6.674 × 10^-11 N⋅m^2/kg^2 * 8 kg * 0.1 kg) / (0.13 m)^2
For the 100 g lead ball:
m1 = 0.1 kg
m2 = 8 kg
r = 0.13 m
Using the equation, we have:
F2 = (G * m1 * m2) / r^2
F2 = (6.674 × 10^-11 N⋅m^2/kg^2 * 0.1 kg * 8 kg) / (0.13 m)^2
Now, let's calculate the values:
F1 = (6.674 × 10^-11 * 8 * 0.1) / (0.13)^2
F1 ≈ 8.8 × 10^-7 N
F2 = (6.674 × 10^-11 * 0.1 * 8) / (0.13)^2
F2 ≈ 8.8 × 10^-7 N
Therefore, the gravitational force exerted by each ball on the other is approximately 8.8 × 10^-7 N.