Using the volume 1.42mL of 95% ethyl alcohol that's required to dissolve 0.3g at 78 C, how do i find how much sulfanilamide that will remain in the mother liquor after the mixture is cooled to 0 C? (at 0 degrees=14mg/mL is the solubility)

thanks

To find out how much sulfanilamide will remain in the mother liquor after the mixture is cooled to 0 degrees Celsius, we need to determine if sulfanilamide will precipitate out of the solution at this temperature.

Given information:
- Volume of ethyl alcohol used: 1.42 mL
- Concentration of ethyl alcohol: 95%
- Mass of sulfanilamide: 0.3 g
- Solubility of sulfanilamide at 0 degrees Celsius: 14 mg/mL

To solve this problem, we need to first calculate the maximum amount of sulfanilamide that can dissolve in the ethyl alcohol at 78 degrees Celsius. Then, we compare that value to the solubility of sulfanilamide at 0 degrees Celsius to determine if it will precipitate out at this temperature.

Step 1: Calculate the maximum amount of sulfanilamide that can dissolve in the ethyl alcohol at 78 degrees Celsius.
- The concentration of ethyl alcohol is given as a percentage. To convert it to a decimal, divide by 100: 95% / 100 = 0.95
- The total volume of the solution is the sum of the volume of the ethyl alcohol and the volume of the sulfanilamide.
- The volume of the ethyl alcohol is given as 1.42 mL.
- The initial volume of the sulfanilamide can be calculated using its density, which is needed to convert mass to volume.
- The density of sulfanilamide is not provided in the given information, so we cannot determine the initial volume of sulfanilamide. Without this information, we cannot calculate the maximum amount of sulfanilamide that can dissolve in the ethyl alcohol at 78 degrees Celsius.

Without the initial volume or density of sulfanilamide, we cannot proceed with the calculation to find how much sulfanilamide will remain in the mother liquor after cooling to 0 degrees Celsius. Please provide the initial volume or density of sulfanilamide so that we can continue with the calculation.

See my note to this same question up about a page.