posted by Tori carr on .
A 4 kg wooden block rest on a table. the coefficient of friction between the block and the table is .40. a 5kg mass is attached to the block by a horizontal string passed over a frictionless pulley of neglible mass what is the acceleration of the block when the 5 kg mass is released? what is the tension in the string during the acceleration?
Force applied =5kgx9.8= 49N
Force Against (friction)=4kgx9.8x.4=15.68
first to find the Acceleration...
49-15.69=Total Force= 33.32N
F=MA F/M=A 33.32/9(both blocks)= 3.702m/ss
Now for Tension..