Posted by **Veronica ** on Tuesday, February 2, 2010 at 4:16pm.

A 3.00 kg object has a velocity (5.20 ihat - 2.40 jhat) m/s. (Note: From the definition of the dot product, v2 = vvec·vvec.)

(a) What is its kinetic energy at this time?

Could some one just please show me how to convert the velocity vector into the "regular" form?

Thank You

- PHysics -
**drwls**, Tuesday, February 2, 2010 at 4:40pm
The vector form you were given is fairly standard. When you take the dot product of the vectopr with itself, you get the scalar magnitude squared, which is what you want for the kinetic energy,

|V|^2 = (5.2)^2 + (2.4)^2

Note that is the same thng as applying the Pythagorean Therem to the two components.

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