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An airplane lands and starts down the runway at a southwest velocity of 41 m/s. What constant acceleration allows it to come to a stop in 1.3 km?

  • Physics -

    Average velocity * time = stopping distance
    (Vo/2) * t = X = 1300
    Also, you can write Vo = a* t for the deceleration time.

    The time t can be eliminated from the two equations, resulting in
    (Vo/2)(Vo/a) = X
    Vo^2 = 2 a X

    Solve for a

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