Posted by **Marcus** on Tuesday, February 2, 2010 at 2:00am.

A rock is dropped from a sea cliff and the sound of it striking the ocean is heard 6.4 s later. If the speed of sound is 340 m/s, how high is the cliff?

- College Physics -
**drwls**, Tuesday, February 2, 2010 at 3:35am
The time of 6.4 s is the sum of the time required for the rock to hit the sea, sqrt (2H/g), and the time for the sound to get back, (H/V).

H = cliff height

V = speed of sound

g = acceleration of gravity

Solve this equation for H:

6.4 = H/340 + sqrt(H/4.9)

That can be turned into a quadratic equation. Only one root will be positive.

- College Physics -
**jim**, Tuesday, September 7, 2010 at 8:40pm
172.35

- College Physics -
**Anonymous**, Sunday, October 26, 2014 at 9:03pm
356.8

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