Posted by **Anonymous** on Tuesday, February 2, 2010 at 1:30am.

Hooke's law describes a certain light spring of unstressed length 36.0 cm. When one end is attached to the top of a door frame and a 6.40 kg object is hung from the other end, the length of the spring is 44.00 cm.

(a) Find its spring constant

I found the correct answer to be k=784 N/m

(b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 170 N. Find the length of the spring in this situation.

I thought the answer was 0.7937m but this is incorrect. I have no other idea on how to solve for part b.

Thank You!

## Answer this Question

## Related Questions

- physic - Hooke's law describes a certain light spring of unstretched length 30.0...
- physics - When a 2.50-kg object is hung vertically on a certain light spring ...
- Physics - When a 2.00-kg object is hung vertically on a certain light spring ...
- Physics - When a 3.00-kg object is hung vertically on a certain light spring ...
- physics - When a 2.60-kg object is hung vertically on a certain light spring ...
- physics - 1)An elastic material has a length of 36cm when a load of 40N is hung ...
- physics - when a 2.50 kg object is hung vertically on a certain light spring ...
- physics - When a 4.48 kg mass is hung vertically on a certain light spring that ...
- physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
- physics mechanics - A block weighing 17 N oscillates at one end of a vertical ...

More Related Questions