Thursday

February 26, 2015

February 26, 2015

Posted by **t** on Monday, February 1, 2010 at 5:31pm.

- calculus -
**bobpursley**, Monday, February 1, 2010 at 5:35pmF'(1)=10+1=11

average= (finalF(s)-initialF(s))/d

= (5d^2+d+4-4)/d= 5d+1

11=5d+1 solve for d.

- calculus -
**drwls**, Monday, February 1, 2010 at 5:41pmI assume that your fucnction is

F(s) = 5s^2 +s + 4.

The instantaneous rate of change of F at s=1 is the value of the derivative at s=1. The derivative is F'(x) = 10s + 1. When s = 1, F' is 11.

The average rate of change of F from 0 to d is [F(d) - F(0)]/d. That equals

(5d^2 + d + 4 - 4)/d = 5d + 1

Set 5d +1 = 11 and solve for d.

I leave that part for you.

**Answer this Question**

**Related Questions**

Calculus - Let F(s)=5s2+5s+4 . Find a value of d greater than 0 such that the ...

calculus (rate of change) - consider the function f(x)=x^2-6x+12 a. find the ...

calculus - i'm not sure how to do this. can someone help, please? thanks! ...

MATH - Create a graph of a function given the following information: The ...

calculus - Let f be defined as follows. F(x)=y=x^2 -7 (a) Find the average rate ...

Calculus - for f(x)=-x^2 +1, which value is the largest magnitude? a) average ...

Math - Could someone help me with these questions, I don't know question c) and ...

AP Calculus - The wind chill is the temperature, in degrees Fahrenheit, a human ...

Math~Reinyyy - Could someone help me with these questions, I don't know ...

Calculus - y = f(x) = x^2 - 6 x (a) Find the average rate of change of y with ...