Posted by rajshekhar on Monday, February 1, 2010 at 6:05am.
let the radius of the cylinder formed be x cm
then the length of the rectangle is 2pi(x)
let the width of the rectangle by y cm
pi(x^2)(y) = 1540
2pi(x)(y) = 440
divide first by second
x/2 = 3/5
x = 7
so area cut out = pi(7)^2 = 49pi
uncut area = 440 - 49pi
ratio of uncut:cut
= (440-49pi)/(49pi)
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