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April 19, 2014

April 19, 2014

Posted by **rajshekhar** on Monday, February 1, 2010 at 6:05am.

- math -
**Reiny**, Monday, February 1, 2010 at 10:25amlet the radius of the cylinder formed be x cm

then the length of the rectangle is 2pi(x)

let the width of the rectangle by y cm

pi(x^2)(y) = 1540

2pi(x)(y) = 440

divide first by second

x/2 = 3/5

x = 7

so area cut out = pi(7)^2 = 49pi

uncut area = 440 - 49pi

ratio of uncut:cut

= (440-49pi)/(49pi)

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