Posted by **becky** on Monday, February 1, 2010 at 5:05am.

Jack usually mows his law in 5 hours. Marilyn can mow the same law in 6 hours. How much time would it take for them to mow the lawn together?

- algebra -
**drwls**, Monday, February 1, 2010 at 5:42am
Add the RATES that they mow lawns.

1/6 lawn/h + 1/5 lawn/h = 11/30 lawn/h

The combined rate times the time reT equals one lawn

11/30 * T = 1 lawn

T = 30/11 hours

- algebra -
**drwls**, Monday, February 1, 2010 at 5:43am
Add the RATES that they each mow lawns.

1/6 lawn/h + 1/5 lawn/h = 11/30 lawn/h

The combined rate times the time required, T, equals one lawn

11/30 * T = 1 lawn

T = 30/11 hours

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