Posted by **becky** on Monday, February 1, 2010 at 5:05am.

Jack usually mows his law in 5 hours. Marilyn can mow the same law in 6 hours. How much time would it take for them to mow the lawn together?

- algebra -
**drwls**, Monday, February 1, 2010 at 5:42am
Add the RATES that they mow lawns.

1/6 lawn/h + 1/5 lawn/h = 11/30 lawn/h

The combined rate times the time reT equals one lawn

11/30 * T = 1 lawn

T = 30/11 hours

- algebra -
**drwls**, Monday, February 1, 2010 at 5:43am
Add the RATES that they each mow lawns.

1/6 lawn/h + 1/5 lawn/h = 11/30 lawn/h

The combined rate times the time required, T, equals one lawn

11/30 * T = 1 lawn

T = 30/11 hours

## Answer This Question

## Related Questions

- algebra - Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn ...
- Algebra - Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard ...
- math - Jack usually mows his lawn in 4 hours. Marilyn can mow the same in 5 ...
- alegbra - Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard ...
- Math - Jack usually mows his lawn in three hours. Marilyn can mow the same yard ...
- MATH - Jack usually mows his lawn in 3 hours. Marilyn can mow the same yard in 5...
- algebra - jack usually mows his lawn in 4 hours mariltn can mow the same yard in...
- algebra - Jack usually mows his lawn in 4hrs Marilyn can mow the same yard in ...
- Algebra II - Jack usually mows his lawn in 6 hours. Marilyn can mow the same ...
- math/117 - Jack usually mowes his lawn in 7 hours. Marilyn can mow the same yard...

More Related Questions