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April 1, 2015

April 1, 2015

Posted by **cynthia** on Sunday, January 31, 2010 at 10:30pm.

thanks for the help!

- math -
**drwls**, Monday, February 1, 2010 at 9:20amAssuming the function is quadratic with an x^2 coefficient of 1,

in the form ax^2 + bx + c = 0.

x = [-b +/- sqrt(b^2 -4ac)]/2a

root sum = -b/a = -b

root product = (1/4a^2)*(-4ac) = -c

x^2 -11x -11 = 0 is the function

Roots are (1/2)(11 + sqrt165)

and (1/2)(11 - sqrt165)

There are many other functions that would meet your criteria, but all of the quadratic ones must be a multiple of the one above.

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