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January 28, 2015

January 28, 2015

Posted by **Momo** on Saturday, January 30, 2010 at 1:53pm.

(x/a)+(y/b)+(z/c) = 1, for c

This is what I have so far:

z/c = 1-(x/a)-(y/b)

z/c = 1-[(xb-ay)/ab]

z/c=(ab/ab)-[(xb-ay)/ab]

z/c=(ab-xb-ay)/ab

...I'm not sure if it's right so far, and if it is, i don't know where to go after that. Help?

Thanks!

- Math -
**Damon**, Saturday, January 30, 2010 at 3:57pmz/c=(ab/ab)-[(xb-ay)/ab]

z/c=(ab-xb-ay)/ab

sign wrong I think

z/c=(ab-xb+ay)/ab { - - is +}

c (ab-xb+ay) = a b z

c = a b z / (ab-xb+ay)

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