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October 2, 2014

October 2, 2014

Posted by **Physics** on Friday, January 29, 2010 at 10:30pm.

what time before rock hits ground.

the horizontal distance the rock traveled from base of cliff.?

my answer is 4.08 sec before rock hits ground

81.6 m distance traveled from base of cliff

- Gweedo8 -
**drwls**, Saturday, January 30, 2010 at 1:05amThe height of the rock above the base of the cliff is:

Y = 100 + 40 sin 42 t - 4.905 t^2

= 100 + 26.765 t - 4.905 t^2.

When t = 4.08, Y = 127 m

Your answer is incorrect.

Solve for t when Y = 0

Then multiply that time by 40 m/s*cos 42, the horizontal velocity component.

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