Posted by **Jennifer** on Friday, January 29, 2010 at 10:15pm.

Two cars approach each other from an initial distance of 2400 m. Car A is moving to the E at a constant rate speed of 40ms. Car B is moving to the W at a speed of 10ms but is accelarating at a rate of 2.00ms^2.

What is the time before the cars meet

the distance a traveled before meeting b

the relative speed at which the cars hit.

- Physics -
**drwls**, Saturday, January 30, 2010 at 12:42am
Call x = 0 the location were Car A starts. Call that car's location X1.

Car B then starts at x = 2400. Call its location X2

X1 = 40 t

X2 = 2400 - 10 t - t^2.

They meet when X1 = X2.

40t = 2400 -10 t - t^2

Rearrange that to read

t^2 +50 t -2400 = 0

(t +80)(t-30) = 0

Solve for the time t that is a positive root of that equation.

Use that value of t to solve for the location where they meet. The relative velocity is V1 - V2. But V2 is negative, so you end up adding the speeds of the cars at time t.

## Answer this Question

## Related Questions

- Physics - Two stunt drivers drive directly toward each other. At time t=0 the ...
- science - Two stunt drivers drive directly toward each other. At time t=0 the ...
- Physics - Two cars cover the same distance in a straight line. Car A covers the...
- physics - Two cars cover the same distance in a straight line. Car A covers the ...
- physics - Two cars are traveling at the same constant speed v. Car A is moving ...
- Physics . pls help me :) - Two train cars are on a straight, horizontal track. ...
- Physics - A 1000-kg car moving east at 80 km/h collides head-on with a 1500-kg ...
- physics - HI. Can someone please help me with this question. Two identical cars ...
- physics - A police officer investigating an accident estimates that a moving car...
- Physics - Two cars are initially 10.5 km apart on a straight road. If the cars ...

More Related Questions