Thursday
March 5, 2015

Homework Help: chemistry

Posted by Krissy on Friday, January 29, 2010 at 6:20pm.

please check if I did this right ...

calculate the mass of white solid CaCO3 that forms when 98ml of a 0.1M Ca(NO3)2 solution is mixed with 54 ml of a 2.5M Na2CO3 solution.

Ca(NO3)2 + 2NaCO3 -> Ca(CO3)2 + 2NaNO3

.098*0.1 =.0090
.054*2.5 =.135

limiting reactant is Ca(NO3)2

.0090 * 160.1 = 1.44g

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