posted by Fred on .
How many liters of oxygen gas at 153 degrees celsius and 0.820 atm can be produced by the decomposition of 22.4 g of solid KClO3? (The other decomposition product is solid potassium chloride)
1. Write the equation and balance it.
2. Convert what you have (KClO3) to moles. # moles = grams/molar mass.
3. Using the coefficient in the balanced equation, convert mole KClO3 to moles O2.
4. Now use PV = nRT to convert moles O2 at STP to liters of O2 at the other conditions.
Post your work if you get stuck.