Posted by Cal on Friday, January 29, 2010 at 8:21am.
In a series capacitor configuration, each capacitor has the same charge. The voltage across the "ith" one is Vi = Q/Ci The smallest Ci has the largest voltage drop.
The equivalent capacitiance C of the series of capacitors is LESS than any individual one, since
1/C = 1/C1 + 1/C2 + 1/C3
The largest voltage appears across the capacitor with the smallest capacitance. That is the statement you should have chosen
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