A 4.58 m solution of the solute methylene chloride dissolved in the solvent acetone is available. Calculate the mass ( kg ) of the solution that must be taken to obtain 0.8848 kg of methylene chloride.

density:
CH2Cl2-1.327 (g/mL)
(CH3)2CO-0.7899 (g/mL)

This is worked the same way as the CH2Cl2 problem. We prefer that you not use more than one screen name when posting problems. It helps us keep people straight.

To calculate the mass (in kg) of the solution required to obtain a specific mass of methylene chloride, you need to consider the concentration and densities of the solute and solvent.

The given concentration of the solution is 4.58 m, which means there are 4.58 moles of methylene chloride per liter of the solution.

First, calculate the number of moles of methylene chloride required using its given mass.

Given mass of methylene chloride = 0.8848 kg

To convert the mass from kg to g:
0.8848 kg * 1000 g/kg = 884.8 g

Now, calculate the number of moles using the molar mass of methylene chloride (84.93 g/mol):
Number of moles of methylene chloride = mass / molar mass
Number of moles of methylene chloride = 884.8 g / 84.93 g/mol

Next, convert the volume of the solution required using the density of each component.

Density of methylene chloride (CH2Cl2) = 1.327 g/mL
Density of acetone ((CH3)2CO) = 0.7899 g/mL

From the concentration given, 4.58 m, we know that there are 4.58 moles of CH2Cl2 per liter of solution. Therefore, the moles of CH2Cl2 in the solution can be calculated as:

Moles of CH2Cl2 in the solution = concentration * volume of solution (in L)
4.58 mol/L * volume = number of moles of CH2Cl2

To calculate the volume of the solution required, we need to convert the moles of CH2Cl2 to grams and then determine the volume based on the densities.

First, calculate the mass of CH2Cl2 required in grams:
Mass of CH2Cl2 = number of moles of CH2Cl2 * molar mass
Mass of CH2Cl2 = (number of moles of CH2Cl2) * 84.93 g/mol

Then, calculate the volume of the solution required in milliliters (mL) using the densities:
Volume of solution (in mL) = (mass of CH2Cl2 / density of CH2Cl2) + (mass of acetone / density of acetone)

Finally, convert the volume from milliliters to liters:
Volume of solution (in L) = Volume of solution (in mL) / 1000

Now you have the volume of the solution required to obtain the specific mass of methylene chloride.