what is the natural logarithm of (4x-1)=36
you mean , solve ln(4x-1) = 36 ?
if so, then
e^36 = 4x-1
4x = e^36 - 1
x = (e^36 - 1)/4 , a rather large number.
To find the natural logarithm of an equation, we need to isolate the logarithmic term on one side of the equation.
Let's solve the equation step by step:
1. Start with the equation: ln(4x - 1) = 36.
2. To isolate the logarithmic term, we need to get rid of the natural logarithm. The opposite operation of taking the natural logarithm is the exponential function e^x. So, we can rewrite the equation as: e^(ln(4x - 1)) = e^36.
3. Applying the exponential function on both sides, we get: 4x - 1 = e^36.
4. Next, let's isolate the variable on one side. Add 1 to both sides: 4x = e^36 + 1.
5. Finally, divide both sides by 4: x = (e^36 + 1) / 4.
So, the natural logarithm of (4x - 1) = 36 is x = (e^36 + 1) / 4.