A runner traveling with an initial velocity of 3.0 m/s accelerates at a constant rate of 1.7 m/s2 for a time of 3 seconds. What distance does the runner cover during this process?
4.5
To find the distance covered by the runner, you can use the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given:
Initial velocity (u) = 3.0 m/s
Acceleration (a) = 1.7 m/s^2
Time (t) = 3 seconds
Substituting the values into the equation:
distance = 3.0 m/s * 3 seconds + (1/2) * 1.7 m/s^2 * (3 seconds)^2
Simplifying the equation:
distance = 9.0 m + (1/2) * 1.7 m/s^2 * 9 s^2
distance = 9.0 m + (1/2) * 1.7 m/s^2 * 81 s^2
distance = 9.0 m + 0.85 m/s^2 * 81 s^2
distance = 9.0 m + 68.85 m
distance = 77.85 m
Therefore, the runner covers a distance of 77.85 meters during this process.