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April 20, 2014

April 20, 2014

Posted by **Ashley** on Thursday, January 28, 2010 at 2:03pm.

The perimeter of a rectangle is 72m. If the width were doubled and the length were increasd by 9m, then the perimeter would be 114m. What are the dimentions?

- College Algebra -
**bobpursley**, Thursday, January 28, 2010 at 2:18pm2L+2W=72

2(2W) + 2(L+9)=114

check that.

- College Algebra -
**Ashley**, Thursday, January 28, 2010 at 2:33pmDoes this mean that the dimentions are 72 and 114 or do you take it father to find what w & l are which I think might be w=12 and l=24. does that sound right?

- College Algebra -
**bobpursley**, Thursday, January 28, 2010 at 3:04pmOf course you have to find width w, and length L.

I would go back and check W=12, L=24 in the original equations. If they check, you are home bound.

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