A liter of 2M NaOH solution contains how many grams of NaOH?
Molarity (M) = moles of solute / liters of solution
2M = moles of NaOH / 1.0 L solution
*Multiply both sides by 1.0 to get moles of NaOH
Moles of NaOH = 2 moles
2 moles NaOH 39.99 g NaOH / 1 mol NaOH
Grams NaOH = 79.98 g (not counting sig figs)
I don't know if this is correct but...
Oh, I'm not much of a chemist, but if you're talking about 2M NaOH solution, I can tell you that the "M" probably doesn't stand for "Munchkins." Let's see if I can calculate this for you.
To find out how many grams of NaOH are in a liter of 2M NaOH solution, we need to rely on a little formula: Molarity (M) = moles of solute / volume of solution (in liters).
Since you have a 2M solution, that means you have 2 moles of NaOH in 1 liter of solution. To convert moles to grams, we need to know the molar mass of NaOH which is approximately 40 g/mol.
So, multiplying the molar mass (40 g/mol) by the number of moles (2 moles), we get 80 grams of NaOH in a liter of 2M NaOH solution.
Pretty neat, huh? Seems like NaOH is pulling its weight in grams!
To determine the number of grams of NaOH in a liter of 2M NaOH solution, you need to know the molar mass of NaOH.
The molar mass of NaOH can be calculated by adding up the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).
The atomic masses are:
- Sodium (Na): 22.99 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
So, the molar mass of NaOH is calculated as follows:
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
Summing these atomic masses gives:
22.99 + 16.00 + 1.01 = 40.00 g/mol
Therefore, the molar mass of NaOH is 40.00 g/mol.
Now, to find the number of grams of NaOH in a liter of 2M NaOH solution, you can use the following equation:
Grams of NaOH = Molarity (M) × Volume (L) × Molar Mass (g/mol)
In this case, the molarity is 2M, and the volume is 1 liter.
Grams of NaOH = 2M × 1 L × 40.00 g/mol
Grams of NaOH = 80.00 grams of NaOH
So, a liter of 2M NaOH solution contains 80.00 grams of NaOH.
To find out how many grams of NaOH are in a liter of 2M (molar) NaOH solution, you need to use the formula:
Mass = Molarity × Volume × Molar Mass
First, let's calculate the molar mass of NaOH:
The molar mass of Na (Sodium) is approximately 23 grams per mole, and the molar mass of O (Oxygen) is approximately 16 grams per mole. The molar mass of H (Hydrogen) is approximately 1 gram per mole.
Adding these together, we get:
Na = 23 grams/mol
O = 16 grams/mol
H = 1 gram/mol
NaOH (Sodium Hydroxide) consists of one atom of Na, one atom of O, and one atom of H, so its molar mass is:
(23 grams/mol of Na) + (16 grams/mol of O) + (1 gram/mol of H) = 40 grams/mol
Now, we can calculate the mass of NaOH (in grams) in a liter of 2M NaOH solution:
Molarity = 2 moles/L
Volume = 1 L
Molar Mass of NaOH = 40 grams/mol
Mass = (2 moles/L) × (1 L) × (40 grams/mol)
Cancel out the units:
Mass = 2 × 40 grams
Now, you can calculate the answer:
Mass = 80 grams
Therefore, a liter of 2M NaOH solution contains 80 grams of NaOH.
M = mols/L
moles = g/molar mass.
Post your work if you get stuck.